Writing Equations as Dot Products

Writing equations as dot products

Here is the question: find a vector v that is perpendicular to 1, comma, one-half, (1, 1/2).
Find v perp to (1,12)
The answer is we can check if it's perpendicular by taking the dot product. We want the dot
product of v1 and v2 to be 0. If we write out this dot product, we get v1 plus one-half of v2.
0=*1,12=v1+12v2
So, there are many possible solutions to this problem. If you pick any number v1, then you
can figure out what v2 has to be to get this to add up to zero.

Here are a couple. For example, vi could be negative 1, and then v2 would have to be 2
to get this thing to add up to 0. Or if v1 were negative one-half, then this would have to
equal 1 to get the sum to be 0.
-1,2 or (-12,1)
Pretty simple.
Let's try to visualize the vectors to check that they are working as expected.

It is better to draw labeled vectors so that these lengths are equal so the angles look right.
The vector is here, 1, a half. And then, negative 1 is here. Thus, here is the vector
negative 1, comma, 2.
[Graph]
Look logically.
Here is negative one-half, 1 drawn
[Graph]
These two vectors share the same direction.
That is reasonable because they're both perpendicular to one, comma, a half. That is why
they are going in the same direction.
We can see from the picture that there should be a lot of them, cause you are able to take
any vector in this direction, and it'11 be perpendicular to 1, comma, 1/2.

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Last time these also
were in the same direction. Because this vector is 2 times that vector.
It all makes sense.
Thus, there are many vectors that are perpendicular to this one and they all go along this
line. Now, let us examine the question. "How do we find a vector that is perpendicular to a
line?"
Here is our new question. Given the line × + ½ y = 0, find a vector perpendicular to it.
x+12y=0
Thus, to solve this problem, it is helpful to look for a hidden dot product.
A dot product is familiar to us. It is common in geometry that to write some expressions as
dot products.
Dot products are notated as a scalar times a vector, but we could write this one as a
hidden dot product.
So x plus 1/2 y, it can be written as (x, comma, y) dotted with (1, comma, 1/2).
x+1/2y=(x,y)*(1,1/2)
It turns out that writing it that way is amazing, it is helpful with understanding the meaning.
Remembering that, draw an image of this line and draw in this vector. this vector is going
to be a main thing.
x-axis, y-axis. Thus, the line is: × + ½ y = 0. And we draw in this vector with a magnitude of
one-half because it comes up in that formula.
It will help us to have it in the picture, so to speak, to think about what everything means.
Here it is the vector one, comma, a half.
[Graph]
Let's suppose we have a point (x, y) on the line; then perhaps its coordinates are (x,
comma, y).
[Graph]
So, if x and y satisfy this equation, then O equals x plus one-half y.
0=x+1/2y
That's what does it mean for (x, y) to be on the line.
We will now see if this gives us an insight into how to write x + one half y as a dot product.
Let's go.
So it is (x, y) dotted with (one, comma, one-half).
0=x+1/2y=(x, y)*(1, 1/2)
Now, this dot product is O. This tells us that the vector (y) is perpendicular to the vector
(1, comma, a half.
Let's draw the vector (x, y) in our picture. It's the vector that goes from the origin to (x, y).
Here it is.
This equation shows that the vector is perpendicular to that vector. So there is a right
angle here
[Graph]
We see that the vector (1, comma, one-half is perpendicular to this line.