Additional Mathematics Sba Topics

To fulfill this task the use of calculus is needed along with other mathematical ethos to help design a best suitable and cheap packaging that will be used to carry a grand amount of smaller products while cost remain in a stead/safe amount. Mathematical Formulation Below is a list of formulas applied to each question A. Tan = B. Substitution Area of triangle + Area of rectangle= Area of pentagon C. Differentiation D. The quadratic equation The quadratic formula OR Factorization of the quadratic formula Problem solution yes D CACM A Problem diagram c i) F is the mid-point of line BE and It’s also the perpendicular of triangle EAI.

Essay Example on Additional Mathematics Sba Topics

The line OAF cuts triangle OAF in half resulting in two isosceles triangles. Since CUBICAL= CAFE and DC=BE, then FEB. and BEEF are both equal to corn. , , then Therefore ii) Since the total cross-sectional area is CACM then: Make y the subject in equation (i) Now sub (i) into (ii) Maximum area When the maximum area: Therefore the maximum cross-sectional area is 540 When the equation is divided by 60 it becomes: These are the two possible values of x that satisfies the maximum cross- sectional area being 300 300 480 540 Prism length=CM

Since x=l, cross-sectional area=300 and cross-sectional perimeter=CACM Volume of prism= When the sides of the container is opened up it makes a net consisting off faces, 2 pentagonal faces and 5 rectangular faces.

Length=cross-sectional perimeter=CACM Width-?prism length=CM Area of -?450 Total surface area (sum of the areas of each face) = Cross-sectional area+ area of rectangles +450 =1050 Fixed costs=$6000 Variable costs-? and Average costs (AC) – For average cost to be a minimum X=600{Therefore 600 units has to be produced to maintain average cost at its minimum level.

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Since x=600 gives a minimum value Application of Solution Since x (the number of units produced) is equaled to 600, the average cost Of the product using the formula: Therefore the possible minimum average cost is $25 per unit Conclusion It was determined that the Trine Chocolate delights Ltd. Had to produce 600 units at the minimum average cost of $25 per tin of chocolates. Also the maximum cross-sectional area was determined to be 300 if the value of x was either CM or LLC. Since x (the number Of units produced) is equaled to 600, the average cost Of either CM or 1 CM.